Base | Representation |
---|---|
bin | 1100000011011111110111… |
… | …1000010011011100101010 |
3 | 1201221002111022200122110210 |
4 | 3000313331320103130222 |
5 | 3214124132234103110 |
6 | 44104524422521550 |
7 | 2535405155622135 |
oct | 300677570233452 |
9 | 51832438618423 |
10 | 13254233503530 |
11 | 42500a8303898 |
12 | 15a0913b962b6 |
13 | 751b3ab53886 |
14 | 33b718bb121c |
15 | 17eb8de9c520 |
hex | c0dfde1372a |
13254233503530 has 32 divisors (see below), whose sum is σ = 31812352387200. Its totient is φ = 3534218714432.
The previous prime is 13254233503517. The next prime is 13254233503541. The reversal of 13254233503530 is 3530533245231.
It is a super-3 number, since 3×132542335035303 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14779245 + ... + 15650384.
It is an arithmetic number, because the mean of its divisors is an integer number (994136012100).
Almost surely, 213254233503530 is an apocalyptic number.
13254233503530 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13254233503530 is an abundant number, since it is smaller than the sum of its proper divisors (18558118883670).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13254233503530 is a wasteful number, since it uses less digits than its factorization.
13254233503530 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30444158.
The product of its (nonzero) digits is 486000, while the sum is 39.
Adding to 13254233503530 its reverse (3530533245231), we get a palindrome (16784766748761).
The spelling of 13254233503530 in words is "thirteen trillion, two hundred fifty-four billion, two hundred thirty-three million, five hundred three thousand, five hundred thirty".
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