132542807 has 2 divisors, whose sum is σ = 132542808. Its totient is φ = 132542806.

The previous prime is 132542779. The next prime is 132542819. The reversal of 132542807 is 708245231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132542807 - 2⁸ = 132542551 is a prime.

It is a super-3 number, since 3×132542807³ (a number of 25 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132542827) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66271403 + 66271404.

It is an arithmetic number, because the mean of its divisors is an integer number (66271404).

Almost surely, 2^132542807 is an apocalyptic number.

132542807 is a deficient number, since it is larger than the sum of its proper divisors (1).

132542807 is an equidigital number, since it uses as much as digits as its factorization.

132542807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 32.

The square root of 132542807 is about 11512.7237003239. The cubic root of 132542807 is about 509.8613066408.

It can be divided in two parts, 13254 and 2807, that added together give a palindrome (16061).

The spelling of 132542807 in words is "one hundred thirty-two million, five hundred forty-two thousand, eight hundred seven".