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1325523503981 is a prime number
BaseRepresentation
bin10011010010011111010…
…110111000101101101101
311200201102000022210111102
4103102133112320231231
5133204133004111411
62452534224532445
7164523464611415
oct23223726705555
94621360283442
101325523503981
11471173509536
12194a8b181125
1397cc4c25011
1448227285645
152472ea54d3b
hex1349f5b8b6d

1325523503981 has 2 divisors, whose sum is σ = 1325523503982. Its totient is φ = 1325523503980.

The previous prime is 1325523503963. The next prime is 1325523504023. The reversal of 1325523503981 is 1893053255231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 756449407081 + 569074096900 = 869741^2 + 754370^2 .

It is a cyclic number.

It is not a de Polignac number, because 1325523503981 - 210 = 1325523502957 is a prime.

It is a super-3 number, since 3×13255235039813 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1325523503911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662761751990 + 662761751991.

It is an arithmetic number, because the mean of its divisors is an integer number (662761751991).

Almost surely, 21325523503981 is an apocalyptic number.

It is an amenable number.

1325523503981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1325523503981 is an equidigital number, since it uses as much as digits as its factorization.

1325523503981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972000, while the sum is 47.

The spelling of 1325523503981 in words is "one trillion, three hundred twenty-five billion, five hundred twenty-three million, five hundred three thousand, nine hundred eighty-one".