Base | Representation |
---|---|
bin | 10011010010011111010… |
… | …110111000101110000000 |
3 | 11200201102000022210112010 |
4 | 103102133112320232000 |
5 | 133204133004112000 |
6 | 2452534224532520 |
7 | 164523464611443 |
oct | 23223726705600 |
9 | 4621360283463 |
10 | 1325523504000 |
11 | 471173509553 |
12 | 194a8b181140 |
13 | 97cc4c25027 |
14 | 4822728565a |
15 | 2472ea54d50 |
hex | 1349f5b8b80 |
1325523504000 has 256 divisors, whose sum is σ = 4496306031360. Its totient is φ = 345252096000.
The previous prime is 1325523503981. The next prime is 1325523504023. The reversal of 1325523504000 is 4053255231.
It is a super-3 number, since 3×13255235040003 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1742895 + ... + 2385105.
It is an arithmetic number, because the mean of its divisors is an integer number (17563695435).
Almost surely, 21325523504000 is an apocalyptic number.
1325523504000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1325523504000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2248153015680).
1325523504000 is an abundant number, since it is smaller than the sum of its proper divisors (3170782527360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1325523504000 is an equidigital number, since it uses as much as digits as its factorization.
1325523504000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 642286 (or 642264 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 30.
Adding to 1325523504000 its reverse (4053255231), we get a palindrome (1329576759231).
It can be divided in two parts, 1325 and 523504000, that added together give a palindrome (523505325).
The spelling of 1325523504000 in words is "one trillion, three hundred twenty-five billion, five hundred twenty-three million, five hundred four thousand".
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