Base | Representation |
---|---|
bin | 1100000011100100110010… |
… | …1111001001001101000101 |
3 | 1201221012220112010221122202 |
4 | 3000321030233021031011 |
5 | 3214134334431033331 |
6 | 44105304003204245 |
7 | 2535453022131416 |
oct | 300711457111505 |
9 | 51835815127582 |
10 | 13255556502341 |
11 | 425071708a43a |
12 | 15a1023076685 |
13 | 751cbbc81bca |
14 | 33b80279b80d |
15 | 17ec1a1d1ecb |
hex | c0e4cbc9345 |
13255556502341 has 2 divisors, whose sum is σ = 13255556502342. Its totient is φ = 13255556502340.
The previous prime is 13255556502313. The next prime is 13255556502347. The reversal of 13255556502341 is 14320565555231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13005731471716 + 249825030625 = 3606346^2 + 499825^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13255556502341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13255556502347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627778251170 + 6627778251171.
It is an arithmetic number, because the mean of its divisors is an integer number (6627778251171).
Almost surely, 213255556502341 is an apocalyptic number.
It is an amenable number.
13255556502341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13255556502341 is an equidigital number, since it uses as much as digits as its factorization.
13255556502341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700000, while the sum is 47.
The spelling of 13255556502341 in words is "thirteen trillion, two hundred fifty-five billion, five hundred fifty-six million, five hundred two thousand, three hundred forty-one".
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