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13255556502341 is a prime number
BaseRepresentation
bin1100000011100100110010…
…1111001001001101000101
31201221012220112010221122202
43000321030233021031011
53214134334431033331
644105304003204245
72535453022131416
oct300711457111505
951835815127582
1013255556502341
11425071708a43a
1215a1023076685
13751cbbc81bca
1433b80279b80d
1517ec1a1d1ecb
hexc0e4cbc9345

13255556502341 has 2 divisors, whose sum is σ = 13255556502342. Its totient is φ = 13255556502340.

The previous prime is 13255556502313. The next prime is 13255556502347. The reversal of 13255556502341 is 14320565555231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13005731471716 + 249825030625 = 3606346^2 + 499825^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13255556502341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13255556502347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6627778251170 + 6627778251171.

It is an arithmetic number, because the mean of its divisors is an integer number (6627778251171).

Almost surely, 213255556502341 is an apocalyptic number.

It is an amenable number.

13255556502341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13255556502341 is an equidigital number, since it uses as much as digits as its factorization.

13255556502341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700000, while the sum is 47.

The spelling of 13255556502341 in words is "thirteen trillion, two hundred fifty-five billion, five hundred fifty-six million, five hundred two thousand, three hundred forty-one".