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13256375254853 is a prime number
BaseRepresentation
bin1100000011100111110110…
…0010011011111101000101
31201221022000120202212221212
43000321331202123331011
53214143024031123403
644105521132021205
72535512223330113
oct300717542337505
951838016685855
1013256375254853
114250aa7269305
1215a1211301805
137520bc79c453
1433b87d408ab3
1517ec670104d8
hexc0e7d89bf45

13256375254853 has 2 divisors, whose sum is σ = 13256375254854. Its totient is φ = 13256375254852.

The previous prime is 13256375254823. The next prime is 13256375254873. The reversal of 13256375254853 is 35845257365231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7583513577124 + 5672861677729 = 2753818^2 + 2381777^2 .

It is an emirp because it is prime and its reverse (35845257365231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13256375254853 - 28 = 13256375254597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13256375254792 and 13256375254801.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13256375254823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6628187627426 + 6628187627427.

It is an arithmetic number, because the mean of its divisors is an integer number (6628187627427).

Almost surely, 213256375254853 is an apocalyptic number.

It is an amenable number.

13256375254853 is a deficient number, since it is larger than the sum of its proper divisors (1).

13256375254853 is an equidigital number, since it uses as much as digits as its factorization.

13256375254853 is an evil number, because the sum of its binary digits is even.

The product of its digits is 90720000, while the sum is 59.

The spelling of 13256375254853 in words is "thirteen trillion, two hundred fifty-six billion, three hundred seventy-five million, two hundred fifty-four thousand, eight hundred fifty-three".