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132614149 is a prime number
BaseRepresentation
bin1111110011110…
…00100000000101
3100020112111102011
413321320200011
5232422123044
621054214221
73200126113
oct771704005
9306474364
10132614149
1168947a78
12384b4371
1321622615
1413880ab3
15b998134
hex7e78805

132614149 has 2 divisors, whose sum is σ = 132614150. Its totient is φ = 132614148.

The previous prime is 132614147. The next prime is 132614171. The reversal of 132614149 is 941416231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131217025 + 1397124 = 11455^2 + 1182^2 .

It is a cyclic number.

It is not a de Polignac number, because 132614149 - 21 = 132614147 is a prime.

Together with 132614147, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132614149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132614147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66307074 + 66307075.

It is an arithmetic number, because the mean of its divisors is an integer number (66307075).

Almost surely, 2132614149 is an apocalyptic number.

It is an amenable number.

132614149 is a deficient number, since it is larger than the sum of its proper divisors (1).

132614149 is an equidigital number, since it uses as much as digits as its factorization.

132614149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 31.

The square root of 132614149 is about 11515.8216814954. The cubic root of 132614149 is about 509.9527689184.

It can be divided in two parts, 13 and 2614149, that added together give a palindrome (2614162).

The spelling of 132614149 in words is "one hundred thirty-two million, six hundred fourteen thousand, one hundred forty-nine".