Base | Representation |
---|---|
bin | 11110001010010011010110… |
… | …011110011001101001011111 |
3 | 122101200011012112210210222001 |
4 | 132022103112132121221133 |
5 | 114341311401233411023 |
6 | 1150042140054303131 |
7 | 36640413001320325 |
oct | 3612232636315137 |
9 | 571604175723861 |
10 | 132649368263263 |
11 | 392a231024a485 |
12 | 12a64405057aa7 |
13 | 5902a21688547 |
14 | 24a8399777d15 |
15 | 10507ab59c6ad |
hex | 78a4d6799a5f |
132649368263263 has 2 divisors, whose sum is σ = 132649368263264. Its totient is φ = 132649368263262.
The previous prime is 132649368263227. The next prime is 132649368263389. The reversal of 132649368263263 is 362362863946231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132649368263263 - 29 = 132649368262751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132649368263195 and 132649368263204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132649368243263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66324684131631 + 66324684131632.
It is an arithmetic number, because the mean of its divisors is an integer number (66324684131632).
Almost surely, 2132649368263263 is an apocalyptic number.
132649368263263 is a deficient number, since it is larger than the sum of its proper divisors (1).
132649368263263 is an equidigital number, since it uses as much as digits as its factorization.
132649368263263 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 241864704, while the sum is 64.
The spelling of 132649368263263 in words is "one hundred thirty-two trillion, six hundred forty-nine billion, three hundred sixty-eight million, two hundred sixty-three thousand, two hundred sixty-three".
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