Base | Representation |
---|---|
bin | 11110001010010111001110… |
… | …001001111010010000000000 |
3 | 122101200112221010212220001221 |
4 | 132022113032021322100000 |
5 | 114341343404023010334 |
6 | 1150044104254404424 |
7 | 36640620656413246 |
oct | 3612271611722000 |
9 | 571615833786057 |
10 | 132653523641344 |
11 | 392a4052909542 |
12 | 12a65184800714 |
13 | 590323453ca44 |
14 | 24a86715b6796 |
15 | 10509512b58b4 |
hex | 78a5ce27a400 |
132653523641344 has 88 divisors (see below), whose sum is σ = 280457133144800. Its totient is φ = 62538077306880.
The previous prime is 132653523641339. The next prime is 132653523641369. The reversal of 132653523641344 is 443146325356231.
It is a super-2 number, since 2×1326535236413442 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132653523641291 and 132653523641300.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12051489 + ... + 20261920.
Almost surely, 2132653523641344 is an apocalyptic number.
It is an amenable number.
132653523641344 is an abundant number, since it is smaller than the sum of its proper divisors (147803609503456).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132653523641344 is a wasteful number, since it uses less digits than its factorization.
132653523641344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32313659 (or 32313641 counting only the distinct ones).
The product of its digits is 18662400, while the sum is 52.
Adding to 132653523641344 its reverse (443146325356231), we get a palindrome (575799848997575).
The spelling of 132653523641344 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred twenty-three million, six hundred forty-one thousand, three hundred forty-four".
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