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132653540141047 is a prime number
BaseRepresentation
bin11110001010010111001111…
…001000110110011111110111
3122101200112222021221011102001
4132022113033020312133313
5114341343422234003142
61150044110044200131
736640621246563322
oct3612271710663767
9571615867834361
10132653540141047
11392a4061158a62
1212a6518a239047
135903237a98b93
1424a867386d7b9
1510509529745b7
hex78a5cf2367f7

132653540141047 has 2 divisors, whose sum is σ = 132653540141048. Its totient is φ = 132653540141046.

The previous prime is 132653540140993. The next prime is 132653540141069. The reversal of 132653540141047 is 740141045356231.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132653540141047 - 223 = 132653531752439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132653540140988 and 132653540141006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132653540141147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66326770070523 + 66326770070524.

It is an arithmetic number, because the mean of its divisors is an integer number (66326770070524).

Almost surely, 2132653540141047 is an apocalyptic number.

132653540141047 is a deficient number, since it is larger than the sum of its proper divisors (1).

132653540141047 is an equidigital number, since it uses as much as digits as its factorization.

132653540141047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1209600, while the sum is 46.

Adding to 132653540141047 its reverse (740141045356231), we get a palindrome (872794585497278).

The spelling of 132653540141047 in words is "one hundred thirty-two trillion, six hundred fifty-three billion, five hundred forty million, one hundred forty-one thousand, forty-seven".