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132654144236153 is a prime number
BaseRepresentation
bin11110001010010111110011…
…001001010010101001111001
3122101200121112101122101002212
4132022113303021102221321
5114341401141411024103
61150044250024104505
736640642233366461
oct3612276311225171
9571617471571085
10132654144236153
11392a4341153611
1212a65318605135
135903302c996c7
1424a86cdba0ba1
15105098aa007d8
hex78a5f3252a79

132654144236153 has 2 divisors, whose sum is σ = 132654144236154. Its totient is φ = 132654144236152.

The previous prime is 132654144236101. The next prime is 132654144236171. The reversal of 132654144236153 is 351632441456231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103100710437904 + 29553433798249 = 10153852^2 + 5436307^2 .

It is a cyclic number.

It is not a de Polignac number, because 132654144236153 - 28 = 132654144235897 is a prime.

It is not a weakly prime, because it can be changed into another prime (132654144236353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66327072118076 + 66327072118077.

It is an arithmetic number, because the mean of its divisors is an integer number (66327072118077).

Almost surely, 2132654144236153 is an apocalyptic number.

It is an amenable number.

132654144236153 is a deficient number, since it is larger than the sum of its proper divisors (1).

132654144236153 is an equidigital number, since it uses as much as digits as its factorization.

132654144236153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6220800, while the sum is 50.

The spelling of 132654144236153 in words is "one hundred thirty-two trillion, six hundred fifty-four billion, one hundred forty-four million, two hundred thirty-six thousand, one hundred fifty-three".