132656320123511 has 2 divisors, whose sum is σ = 132656320123512. Its totient is φ = 132656320123510.

The previous prime is 132656320123447. The next prime is 132656320123513. The reversal of 132656320123511 is 115321023656231.

It is a strong prime.

It is an emirp because it is prime and its reverse (115321023656231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132656320123511 - 2⁶ = 132656320123447 is a prime.

It is a super-3 number, since 3×132656320123511³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 132656320123513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132656320123513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66328160061755 + 66328160061756.

It is an arithmetic number, because the mean of its divisors is an integer number (66328160061756).

Almost surely, 2^{132656320123511} is an apocalyptic number.

132656320123511 is a deficient number, since it is larger than the sum of its proper divisors (1).

132656320123511 is an equidigital number, since it uses as much as digits as its factorization.

132656320123511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 41.

Adding to 132656320123511 its reverse (115321023656231), we get a palindrome (247977343779742).

The spelling of 132656320123511 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, three hundred twenty million, one hundred twenty-three thousand, five hundred eleven".