Base | Representation |
---|---|
bin | 11110001010011010000001… |
… | …000011011001011001000011 |
3 | 122101200211200022120112100020 |
4 | 132022122001003121121003 |
5 | 114341421030403234210 |
6 | 1150045322153224523 |
7 | 36641055233126064 |
oct | 3612320103313103 |
9 | 571624608515306 |
10 | 132656525055555 |
11 | 392a5353055456 |
12 | 12a65881a02143 |
13 | 59035c22cab97 |
14 | 24a887806a56b |
15 | 1050a79a38770 |
hex | 78a6810d9643 |
132656525055555 has 256 divisors, whose sum is σ = 235146240000000. Its totient is φ = 63620923392000.
The previous prime is 132656525055553. The next prime is 132656525055583. The reversal of 132656525055555 is 555550525656231.
It is not a de Polignac number, because 132656525055555 - 21 = 132656525055553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132656525055553) by changing a digit.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 106210187571 + ... + 106210188819.
It is an arithmetic number, because the mean of its divisors is an integer number (918540000000).
Almost surely, 2132656525055555 is an apocalyptic number.
132656525055555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132656525055555 is a deficient number, since it is larger than the sum of its proper divisors (102489714944445).
132656525055555 is a wasteful number, since it uses less digits than its factorization.
132656525055555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2670.
The product of its (nonzero) digits is 168750000, while the sum is 60.
The spelling of 132656525055555 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, five hundred twenty-five million, fifty-five thousand, five hundred fifty-five".
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