Base | Representation |
---|---|
bin | 111101110010011101… |
… | …0000101011101111111 |
3 | 110200111100121111122122 |
4 | 1323210322011131333 |
5 | 4133221444412004 |
6 | 140542351233155 |
7 | 12405111503006 |
oct | 1734472053577 |
9 | 420440544578 |
10 | 132689450879 |
11 | 51300810407 |
12 | 218715187bb |
13 | c68813679b |
14 | 65ca753c3d |
15 | 36b9012cbe |
hex | 1ee4e8577f |
132689450879 has 2 divisors, whose sum is σ = 132689450880. Its totient is φ = 132689450878.
The previous prime is 132689450843. The next prime is 132689450941. The reversal of 132689450879 is 978054986231.
It is an a-pointer prime, because the next prime (132689450941) can be obtained adding 132689450879 to its sum of digits (62).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132689450879 - 212 = 132689446783 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132689450809) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66344725439 + 66344725440.
It is an arithmetic number, because the mean of its divisors is an integer number (66344725440).
It is a 1-persistent number, because it is pandigital, but 2⋅132689450879 = 265378901758 is not.
Almost surely, 2132689450879 is an apocalyptic number.
132689450879 is a deficient number, since it is larger than the sum of its proper divisors (1).
132689450879 is an equidigital number, since it uses as much as digits as its factorization.
132689450879 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26127360, while the sum is 62.
The spelling of 132689450879 in words is "one hundred thirty-two billion, six hundred eighty-nine million, four hundred fifty thousand, eight hundred seventy-nine".
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