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132701101107257 is a prime number
BaseRepresentation
bin11110001011000011100001…
…111111100010100000111001
3122101212002201220021120200002
4132023003201333202200321
5114343133323340413012
61150122013320522345
736644223664250354
oct3613034177424071
9571762656246602
10132701101107257
1139312248078901
1212a724423203b5
135907877434137
1424aaaa629d29b
151051cd81327c2
hex78b0e1fe2839

132701101107257 has 2 divisors, whose sum is σ = 132701101107258. Its totient is φ = 132701101107256.

The previous prime is 132701101107209. The next prime is 132701101107259. The reversal of 132701101107257 is 752701101107231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128063715442576 + 4637385664681 = 11316524^2 + 2153459^2 .

It is a cyclic number.

It is not a de Polignac number, because 132701101107257 - 246 = 62332356929593 is a prime.

Together with 132701101107259, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132701101107257.

It is not a weakly prime, because it can be changed into another prime (132701101107259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66350550553628 + 66350550553629.

It is an arithmetic number, because the mean of its divisors is an integer number (66350550553629).

Almost surely, 2132701101107257 is an apocalyptic number.

It is an amenable number.

132701101107257 is a deficient number, since it is larger than the sum of its proper divisors (1).

132701101107257 is an equidigital number, since it uses as much as digits as its factorization.

132701101107257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20580, while the sum is 38.

The spelling of 132701101107257 in words is "one hundred thirty-two trillion, seven hundred one billion, one hundred one million, one hundred seven thousand, two hundred fifty-seven".