Base | Representation |
---|---|
bin | 1100000100011011110011… |
… | …0011111010011001000110 |
3 | 1201222122000112110211110210 |
4 | 3001012330303322121012 |
5 | 3214410104323434340 |
6 | 44120145052500250 |
7 | 2536514641224210 |
oct | 301067463723106 |
9 | 51878015424423 |
10 | 13270321702470 |
11 | 4256a0370a878 |
12 | 15a3a63a7a686 |
13 | 753502c7b011 |
14 | 33c4037415b0 |
15 | 1802d15b6180 |
hex | c11bccfa646 |
13270321702470 has 128 divisors (see below), whose sum is σ = 37802370816000. Its totient is φ = 2918077443072.
The previous prime is 13270321702447. The next prime is 13270321702481. The reversal of 13270321702470 is 7420712307231.
13270321702470 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×132703217024702 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8903370 + ... + 10286429.
It is an arithmetic number, because the mean of its divisors is an integer number (295331022000).
Almost surely, 213270321702470 is an apocalyptic number.
13270321702470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13270321702470 is an abundant number, since it is smaller than the sum of its proper divisors (24532049113530).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13270321702470 is a wasteful number, since it uses less digits than its factorization.
13270321702470 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19189942.
The product of its (nonzero) digits is 98784, while the sum is 39.
The spelling of 13270321702470 in words is "thirteen trillion, two hundred seventy billion, three hundred twenty-one million, seven hundred two thousand, four hundred seventy".
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