Base | Representation |
---|---|
bin | 111101110011001011… |
… | …0010000100001001111 |
3 | 110200120001002002101111 |
4 | 1323212112100201033 |
5 | 4133244141112031 |
6 | 140545013152451 |
7 | 12405524046442 |
oct | 1734626204117 |
9 | 420501062344 |
10 | 132713613391 |
11 | 51313414027 |
12 | 2187962b727 |
13 | c690146728 |
14 | 65cda43659 |
15 | 36bb1d71b1 |
hex | 1ee659084f |
132713613391 has 2 divisors, whose sum is σ = 132713613392. Its totient is φ = 132713613390.
The previous prime is 132713613379. The next prime is 132713613449. The reversal of 132713613391 is 193316317231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132713613391 - 211 = 132713611343 is a prime.
It is a super-4 number, since 4×1327136133914 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132713613341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66356806695 + 66356806696.
It is an arithmetic number, because the mean of its divisors is an integer number (66356806696).
Almost surely, 2132713613391 is an apocalyptic number.
132713613391 is a deficient number, since it is larger than the sum of its proper divisors (1).
132713613391 is an equidigital number, since it uses as much as digits as its factorization.
132713613391 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 61236, while the sum is 40.
The spelling of 132713613391 in words is "one hundred thirty-two billion, seven hundred thirteen million, six hundred thirteen thousand, three hundred ninety-one".
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