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132713613449 is a prime number
BaseRepresentation
bin111101110011001011…
…0010000100010001001
3110200120001002002110122
41323212112100202021
54133244141112244
6140545013153025
712405524046554
oct1734626204211
9420501062418
10132713613449
115131341407a
122187962b775
13c690146771
1465cda4369b
1536bb1d71ee
hex1ee6590889

132713613449 has 2 divisors, whose sum is σ = 132713613450. Its totient is φ = 132713613448.

The previous prime is 132713613391. The next prime is 132713613451. The reversal of 132713613449 is 944316317231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83148606025 + 49565007424 = 288355^2 + 222632^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132713613449 is a prime.

It is a super-2 number, since 2×1327136134492 (a number of 23 digits) contains 22 as substring.

Together with 132713613451, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132713693449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66356806724 + 66356806725.

It is an arithmetic number, because the mean of its divisors is an integer number (66356806725).

Almost surely, 2132713613449 is an apocalyptic number.

It is an amenable number.

132713613449 is a deficient number, since it is larger than the sum of its proper divisors (1).

132713613449 is an equidigital number, since it uses as much as digits as its factorization.

132713613449 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 326592, while the sum is 44.

The spelling of 132713613449 in words is "one hundred thirty-two billion, seven hundred thirteen million, six hundred thirteen thousand, four hundred forty-nine".