Base | Representation |
---|---|
bin | 111101110111001111… |
… | …1000010000110000011 |
3 | 110200220112221220210111 |
4 | 1323232133002012003 |
5 | 4134034113200311 |
6 | 141010331212151 |
7 | 12412102325101 |
oct | 1735637020603 |
9 | 420815856714 |
10 | 132850131331 |
11 | 51383487a75 |
12 | 218b72a7057 |
13 | c6b2504b88 |
14 | 6603c1cc71 |
15 | 36c81a1d21 |
hex | 1eee7c2183 |
132850131331 has 2 divisors, whose sum is σ = 132850131332. Its totient is φ = 132850131330.
The previous prime is 132850131313. The next prime is 132850131343. The reversal of 132850131331 is 133131058231.
It is a happy number.
Together with previous prime (132850131313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132850131331 - 211 = 132850129283 is a prime.
It is a super-2 number, since 2×1328501313312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132850131293 and 132850131302.
It is not a weakly prime, because it can be changed into another prime (132850131311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66425065665 + 66425065666.
It is an arithmetic number, because the mean of its divisors is an integer number (66425065666).
Almost surely, 2132850131331 is an apocalyptic number.
132850131331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132850131331 is an equidigital number, since it uses as much as digits as its factorization.
132850131331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 31.
Adding to 132850131331 its reverse (133131058231), we get a palindrome (265981189562).
The spelling of 132850131331 in words is "one hundred thirty-two billion, eight hundred fifty million, one hundred thirty-one thousand, three hundred thirty-one".
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