Base | Representation |
---|---|
bin | 111101111000100100… |
… | …1101100100011110110 |
3 | 110201000200010212100222 |
4 | 1323301021230203312 |
5 | 4134132041313000 |
6 | 141015010134342 |
7 | 12413154516566 |
oct | 1736111544366 |
9 | 421020125328 |
10 | 132894869750 |
11 | 513a6764675 |
12 | 2190a2813b2 |
13 | c6bb86a406 |
14 | 6609b46da6 |
15 | 36cc08ca85 |
hex | 1ef126c8f6 |
132894869750 has 16 divisors (see below), whose sum is σ = 248779196640. Its totient is φ = 53157947800.
The previous prime is 132894869729. The next prime is 132894869753. The reversal of 132894869750 is 57968498231.
It is a super-2 number, since 2×1328948697502 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132894869753) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 265789490 + ... + 265789989.
It is an arithmetic number, because the mean of its divisors is an integer number (15548699790).
It is a 1-persistent number, because it is pandigital, but 2⋅132894869750 = 265789739500 is not.
Almost surely, 2132894869750 is an apocalyptic number.
132894869750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132894869750 is a deficient number, since it is larger than the sum of its proper divisors (115884326890).
132894869750 is an equidigital number, since it uses as much as digits as its factorization.
132894869750 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 531579496 (or 531579486 counting only the distinct ones).
The product of its (nonzero) digits is 26127360, while the sum is 62.
The spelling of 132894869750 in words is "one hundred thirty-two billion, eight hundred ninety-four million, eight hundred sixty-nine thousand, seven hundred fifty".
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