Base | Representation |
---|---|
bin | 1100000101100110111010… |
… | …1111110100000001100001 |
3 | 1202001120001212202000210201 |
4 | 3001121232233310001201 |
5 | 3220222404112411231 |
6 | 44133322041425201 |
7 | 2541130440122635 |
oct | 301315657640141 |
9 | 52046055660721 |
10 | 13290486841441 |
11 | 4264511381187 |
12 | 15a795119b201 |
13 | 755397925504 |
14 | 33d397932dc5 |
15 | 180ab1aa2161 |
hex | c166ebf4061 |
13290486841441 has 2 divisors, whose sum is σ = 13290486841442. Its totient is φ = 13290486841440.
The previous prime is 13290486841439. The next prime is 13290486841477. The reversal of 13290486841441 is 14414868409231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12716862377041 + 573624464400 = 3566071^2 + 757380^2 .
It is a cyclic number.
It is not a de Polignac number, because 13290486841441 - 21 = 13290486841439 is a prime.
Together with 13290486841439, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13290486851441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6645243420720 + 6645243420721.
It is an arithmetic number, because the mean of its divisors is an integer number (6645243420721).
Almost surely, 213290486841441 is an apocalyptic number.
It is an amenable number.
13290486841441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13290486841441 is an equidigital number, since it uses as much as digits as its factorization.
13290486841441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5308416, while the sum is 55.
The spelling of 13290486841441 in words is "thirteen trillion, two hundred ninety billion, four hundred eighty-six million, eight hundred forty-one thousand, four hundred forty-one".
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