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13290486841441 is a prime number
BaseRepresentation
bin1100000101100110111010…
…1111110100000001100001
31202001120001212202000210201
43001121232233310001201
53220222404112411231
644133322041425201
72541130440122635
oct301315657640141
952046055660721
1013290486841441
114264511381187
1215a795119b201
13755397925504
1433d397932dc5
15180ab1aa2161
hexc166ebf4061

13290486841441 has 2 divisors, whose sum is σ = 13290486841442. Its totient is φ = 13290486841440.

The previous prime is 13290486841439. The next prime is 13290486841477. The reversal of 13290486841441 is 14414868409231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12716862377041 + 573624464400 = 3566071^2 + 757380^2 .

It is a cyclic number.

It is not a de Polignac number, because 13290486841441 - 21 = 13290486841439 is a prime.

Together with 13290486841439, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13290486851441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6645243420720 + 6645243420721.

It is an arithmetic number, because the mean of its divisors is an integer number (6645243420721).

Almost surely, 213290486841441 is an apocalyptic number.

It is an amenable number.

13290486841441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13290486841441 is an equidigital number, since it uses as much as digits as its factorization.

13290486841441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5308416, while the sum is 55.

The spelling of 13290486841441 in words is "thirteen trillion, two hundred ninety billion, four hundred eighty-six million, eight hundred forty-one thousand, four hundred forty-one".