Base | Representation |
---|---|
bin | 1100000101100110111010… |
… | …1111110100000010000101 |
3 | 1202001120001212202000212001 |
4 | 3001121232233310002011 |
5 | 3220222404112411402 |
6 | 44133322041425301 |
7 | 2541130440123016 |
oct | 301315657640205 |
9 | 52046055660761 |
10 | 13290486841477 |
11 | 426451138120a |
12 | 15a795119b231 |
13 | 755397925531 |
14 | 33d39793300d |
15 | 180ab1aa2187 |
hex | c166ebf4085 |
13290486841477 has 2 divisors, whose sum is σ = 13290486841478. Its totient is φ = 13290486841476.
The previous prime is 13290486841441. The next prime is 13290486841543. The reversal of 13290486841477 is 77414868409231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9364279332321 + 3926207509156 = 3060111^2 + 1981466^2 .
It is a cyclic number.
It is not a de Polignac number, because 13290486841477 - 243 = 4494393819269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13290486841427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6645243420738 + 6645243420739.
It is an arithmetic number, because the mean of its divisors is an integer number (6645243420739).
Almost surely, 213290486841477 is an apocalyptic number.
It is an amenable number.
13290486841477 is a deficient number, since it is larger than the sum of its proper divisors (1).
13290486841477 is an equidigital number, since it uses as much as digits as its factorization.
13290486841477 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 65028096, while the sum is 64.
The spelling of 13290486841477 in words is "thirteen trillion, two hundred ninety billion, four hundred eighty-six million, eight hundred forty-one thousand, four hundred seventy-seven".
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