Base | Representation |
---|---|
bin | 11000110000011001… |
… | …11100001100111011 |
3 | 1021022021021002020122 |
4 | 30120030330030323 |
5 | 204204440304022 |
6 | 10034503043455 |
7 | 650235121514 |
oct | 143014741473 |
9 | 37267232218 |
10 | 13290947387 |
11 | 5700436543 |
12 | 26ab14058b |
13 | 133a750213 |
14 | 901263a0b |
15 | 52bc73742 |
hex | 31833c33b |
13290947387 has 2 divisors, whose sum is σ = 13290947388. Its totient is φ = 13290947386.
The previous prime is 13290947359. The next prime is 13290947389. The reversal of 13290947387 is 78374909231.
13290947387 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13290947387 - 212 = 13290943291 is a prime.
Together with 13290947389, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13290947389) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6645473693 + 6645473694.
It is an arithmetic number, because the mean of its divisors is an integer number (6645473694).
Almost surely, 213290947387 is an apocalyptic number.
13290947387 is a deficient number, since it is larger than the sum of its proper divisors (1).
13290947387 is an equidigital number, since it uses as much as digits as its factorization.
13290947387 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2286144, while the sum is 53.
The spelling of 13290947387 in words is "thirteen billion, two hundred ninety million, nine hundred forty-seven thousand, three hundred eighty-seven".
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