133000117 has 2 divisors, whose sum is σ = 133000118. Its totient is φ = 133000116.

The previous prime is 133000097. The next prime is 133000121. The reversal of 133000117 is 711000331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111386916 + 21613201 = 10554^2 + 4649^2 .

It is an emirp because it is prime and its reverse (711000331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133000117 - 2¹¹ = 132998069 is a prime.

It is a super-3 number, since 3×133000117³ (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 133000117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133000157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66500058 + 66500059.

It is an arithmetic number, because the mean of its divisors is an integer number (66500059).

Almost surely, 2^133000117 is an apocalyptic number.

It is an amenable number.

133000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

133000117 is an equidigital number, since it uses as much as digits as its factorization.

133000117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 16.

The square root of 133000117 is about 11532.5676672630. The cubic root of 133000117 is about 510.4470218800.

Adding to 133000117 its reverse (711000331), we get a palindrome (844000448).

The spelling of 133000117 in words is "one hundred thirty-three million, one hundred seventeen", and thus it is an aban number.