Base | Representation |
---|---|
bin | 10011010110101010011… |
… | …100010100100101000111 |
3 | 11201010222022000012200211 |
4 | 103112222130110211013 |
5 | 133242322114224021 |
6 | 2454555015020251 |
7 | 165042515154040 |
oct | 23265234244507 |
9 | 4633868005624 |
10 | 1330004445511 |
11 | 4730629221a5 |
12 | 19591b96a687 |
13 | 9855a387b01 |
14 | 4853042d8c7 |
15 | 248e312b3e1 |
hex | 135aa714947 |
1330004445511 has 32 divisors (see below), whose sum is σ = 1599414336000. Its totient is φ = 1081804682112.
The previous prime is 1330004445503. The next prime is 1330004445593. The reversal of 1330004445511 is 1155444000331.
It is not a de Polignac number, because 1330004445511 - 23 = 1330004445503 is a prime.
It is a super-2 number, since 2×13300044455112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330004445311) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 75649920 + ... + 75667498.
It is an arithmetic number, because the mean of its divisors is an integer number (49981698000).
Almost surely, 21330004445511 is an apocalyptic number.
1330004445511 is a deficient number, since it is larger than the sum of its proper divisors (269409890489).
1330004445511 is a wasteful number, since it uses less digits than its factorization.
1330004445511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23991.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 1330004445511 its reverse (1155444000331), we get a palindrome (2485448445842).
The spelling of 1330004445511 in words is "one trillion, three hundred thirty billion, four million, four hundred forty-five thousand, five hundred eleven".
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