Base | Representation |
---|---|
bin | 11110001111011010010100… |
… | …100110100000111110011000 |
3 | 122102220201102001210212221011 |
4 | 132033122110212200332120 |
5 | 114413034410301144230 |
6 | 1150511321411223304 |
7 | 40004652101333422 |
oct | 3617322446407630 |
9 | 572821361725834 |
10 | 133000450412440 |
11 | 394181a0a41496 |
12 | 12b004658a7b34 |
13 | 5929b724c7710 |
14 | 24bb382c1d812 |
15 | 10599a860ce2a |
hex | 78f6949a0f98 |
133000450412440 has 32 divisors (see below), whose sum is σ = 322270322154480. Its totient is φ = 49107858613632.
The previous prime is 133000450412437. The next prime is 133000450412491. The reversal of 133000450412440 is 44214054000331.
It is a super-2 number, since 2×1330004504124402 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 127885047954 + ... + 127885048993.
Almost surely, 2133000450412440 is an apocalyptic number.
133000450412440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133000450412440 is an abundant number, since it is smaller than the sum of its proper divisors (189269871742040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133000450412440 is a wasteful number, since it uses less digits than its factorization.
133000450412440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 255770096971 (or 255770096967 counting only the distinct ones).
The product of its (nonzero) digits is 23040, while the sum is 31.
The spelling of 133000450412440 in words is "one hundred thirty-three trillion, four hundred fifty million, four hundred twelve thousand, four hundred forty".
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