Base | Representation |
---|---|
bin | 10011010110101010110… |
… | …101010101100011110111 |
3 | 11201010222202100101001111 |
4 | 103112222311111203313 |
5 | 133242330304100002 |
6 | 2454555411335451 |
7 | 165042624665332 |
oct | 23265265254367 |
9 | 4633882311044 |
10 | 1330011003127 |
11 | 4730665a1014 |
12 | 195921bb1587 |
13 | 9855b842861 |
14 | 48531259619 |
15 | 248e39c43d7 |
hex | 135aad558f7 |
1330011003127 has 2 divisors, whose sum is σ = 1330011003128. Its totient is φ = 1330011003126.
The previous prime is 1330011003089. The next prime is 1330011003149. The reversal of 1330011003127 is 7213001100331.
It is an a-pointer prime, because the next prime (1330011003149) can be obtained adding 1330011003127 to its sum of digits (22).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1330011003127 - 239 = 780255189239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1330011003098 and 1330011003107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330011063127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665005501563 + 665005501564.
It is an arithmetic number, because the mean of its divisors is an integer number (665005501564).
Almost surely, 21330011003127 is an apocalyptic number.
1330011003127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330011003127 is an equidigital number, since it uses as much as digits as its factorization.
1330011003127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 378, while the sum is 22.
Adding to 1330011003127 its reverse (7213001100331), we get a palindrome (8543012103458).
The spelling of 1330011003127 in words is "one trillion, three hundred thirty billion, eleven million, three thousand, one hundred twenty-seven".
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