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13300122099967 is a prime number
BaseRepresentation
bin1100000110001010110100…
…0011011010000011111111
31202002110221101011212200121
43001202231003122003333
53220402122224144332
644141554114435411
72541621265352443
oct301425503320377
952073841155617
1013300122099967
11426860621255a
1215a979bb92b67
13756271b97a11
1433da2d46c823
15180e77913797
hexc18ad0da0ff

13300122099967 has 2 divisors, whose sum is σ = 13300122099968. Its totient is φ = 13300122099966.

The previous prime is 13300122099949. The next prime is 13300122100021. The reversal of 13300122099967 is 76999022100331.

It is a happy number.

13300122099967 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (76999022100331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13300122099967 - 239 = 12750366286079 is a prime.

It is a super-3 number, since 3×133001220999673 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300122099917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650061049983 + 6650061049984.

It is an arithmetic number, because the mean of its divisors is an integer number (6650061049984).

Almost surely, 213300122099967 is an apocalyptic number.

13300122099967 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300122099967 is an equidigital number, since it uses as much as digits as its factorization.

13300122099967 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1102248, while the sum is 52.

The spelling of 13300122099967 in words is "thirteen trillion, three hundred billion, one hundred twenty-two million, ninety-nine thousand, nine hundred sixty-seven".