Base | Representation |
---|---|
bin | 10011010110101011111… |
… | …101111101011111010000 |
3 | 11201011001002011121011101 |
4 | 103112223331331133100 |
5 | 133242400142303130 |
6 | 2455001331354144 |
7 | 165043245546421 |
oct | 23265375753720 |
9 | 4634032147141 |
10 | 1330030041040 |
11 | 473076314528 |
12 | 195928452954 |
13 | 9856277a0ac |
14 | 485339b3648 |
15 | 248e54d51ca |
hex | 135abf7d7d0 |
1330030041040 has 40 divisors (see below), whose sum is σ = 3092728624128. Its totient is φ = 531941688960.
The previous prime is 1330030041023. The next prime is 1330030041049. The reversal of 1330030041040 is 401400300331.
It is a tau number, because it is divible by the number of its divisors (40).
It is a junction number, because it is equal to n+sod(n) for n = 1330030040999 and 1330030041017.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330030041049) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 487792 + ... + 1702351.
Almost surely, 21330030041040 is an apocalyptic number.
1330030041040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1330030041040 is an abundant number, since it is smaller than the sum of its proper divisors (1762698583088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1330030041040 is a wasteful number, since it uses less digits than its factorization.
1330030041040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2197747 (or 2197741 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1330030041040 its reverse (401400300331), we get a palindrome (1731430341371).
The spelling of 1330030041040 in words is "one trillion, three hundred thirty billion, thirty million, forty-one thousand, forty".
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