13300311122320 has 40 divisors (see below), whose sum is σ = 30971315583936. Its totient is φ = 5311850517888.

The previous prime is 13300311122303. The next prime is 13300311122419. The reversal of 13300311122320 is 2322111300331.

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-4 number, since 4×13300311122320⁴ (a number of 54 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13300311122291 and 13300311122300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129228412 + ... + 129331291.

Almost surely, 2^{13300311122320} is an apocalyptic number.

13300311122320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13300311122320 is an abundant number, since it is smaller than the sum of its proper divisors (17671004461616).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13300311122320 is a wasteful number, since it uses less digits than its factorization.

13300311122320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 258560359 (or 258560353 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13300311122320 its reverse (2322111300331), we get a palindrome (15622422422651).

The spelling of 13300311122320 in words is "thirteen trillion, three hundred billion, three hundred eleven million, one hundred twenty-two thousand, three hundred twenty".