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13300403021341 is a prime number
BaseRepresentation
bin1100000110001011110111…
…0011000010011000011101
31202002111122221210011100221
43001202331303002120131
53220403211133140331
644142042031521341
72541631246221262
oct301427563023035
952074587704327
1013300403021341
11426873a845987
1215a985a089251
137562b8145897
1433da588b7269
15180e92404711
hexc18bdcc261d

13300403021341 has 2 divisors, whose sum is σ = 13300403021342. Its totient is φ = 13300403021340.

The previous prime is 13300403021333. The next prime is 13300403021357. The reversal of 13300403021341 is 14312030400331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7988276933316 + 5312126088025 = 2826354^2 + 2304805^2 .

It is a cyclic number.

It is not a de Polignac number, because 13300403021341 - 23 = 13300403021333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13300403021441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650201510670 + 6650201510671.

It is an arithmetic number, because the mean of its divisors is an integer number (6650201510671).

Almost surely, 213300403021341 is an apocalyptic number.

It is an amenable number.

13300403021341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13300403021341 is an equidigital number, since it uses as much as digits as its factorization.

13300403021341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13300403021341 its reverse (14312030400331), we get a palindrome (27612433421672).

The spelling of 13300403021341 in words is "thirteen trillion, three hundred billion, four hundred three million, twenty-one thousand, three hundred forty-one".