Base | Representation |
---|---|
bin | 1100000110001011110111… |
… | …0111101100000000110111 |
3 | 1202002111200001002002122201 |
4 | 3001202331313230000313 |
5 | 3220403211441143224 |
6 | 44142042114005331 |
7 | 2541631262456431 |
oct | 301427567540067 |
9 | 52074601062581 |
10 | 13300404240439 |
11 | 42687404a88a8 |
12 | 15a985a576847 |
13 | 7562b8481744 |
14 | 33da58b13651 |
15 | 180e92595a44 |
hex | c18bddec037 |
13300404240439 has 2 divisors, whose sum is σ = 13300404240440. Its totient is φ = 13300404240438.
The previous prime is 13300404240437. The next prime is 13300404240517. The reversal of 13300404240439 is 93404240400331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13300404240439 - 21 = 13300404240437 is a prime.
Together with 13300404240437, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13300404240398 and 13300404240407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13300404240437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650202120219 + 6650202120220.
It is an arithmetic number, because the mean of its divisors is an integer number (6650202120220).
Almost surely, 213300404240439 is an apocalyptic number.
13300404240439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13300404240439 is an equidigital number, since it uses as much as digits as its factorization.
13300404240439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 37.
The spelling of 13300404240439 in words is "thirteen trillion, three hundred billion, four hundred four million, two hundred forty thousand, four hundred thirty-nine".
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