1330101011 has 2 divisors, whose sum is σ = 1330101012. Its totient is φ = 1330101010.

The previous prime is 1330101001. The next prime is 1330101013. The reversal of 1330101011 is 1101010331.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (1101010331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1330101011 - 2¹⁴ = 1330084627 is a prime.

Together with 1330101013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1330100983 and 1330101001.

It is not a weakly prime, because it can be changed into another prime (1330101013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665050505 + 665050506.

It is an arithmetic number, because the mean of its divisors is an integer number (665050506).

Almost surely, 2^1330101011 is an apocalyptic number.

1330101011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330101011 is an equidigital number, since it uses as much as digits as its factorization.

1330101011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 1330101011 is about 36470.5499135947. The cubic root of 1330101011 is about 1099.7522888497.

Adding to 1330101011 its reverse (1101010331), we get a palindrome (2431111342).

The spelling of 1330101011 in words is "one billion, three hundred thirty million, one hundred one thousand, eleven".