Base | Representation |
---|---|
bin | 1100000110001110001010… |
… | …1001100101010100110100 |
3 | 1202002120021001011222021021 |
4 | 3001203202221211110310 |
5 | 3220410442423100040 |
6 | 44142223235430524 |
7 | 2541652464420106 |
oct | 301434251452464 |
9 | 52076231158237 |
10 | 13301021300020 |
11 | 4268a278488a3 |
12 | 15a99b1155444 |
13 | 75638627125c |
14 | 33dab6a5b576 |
15 | 180ecb83324a |
hex | c18e2a65534 |
13301021300020 has 24 divisors (see below), whose sum is σ = 27932226049224. Its totient is φ = 5320393030656.
The previous prime is 13301021299817. The next prime is 13301021300023. The reversal of 13301021300020 is 2000312010331.
It can be written as a sum of positive squares in 4 ways, for example, as 710858079376 + 12590163220644 = 843124^2 + 3548262^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13301021299967 and 13301021300003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13301021300023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8183464 + ... + 9673216.
It is an arithmetic number, because the mean of its divisors is an integer number (1163842752051).
Almost surely, 213301021300020 is an apocalyptic number.
13301021300020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13301021300020 is an abundant number, since it is smaller than the sum of its proper divisors (14631204749204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13301021300020 is a wasteful number, since it uses less digits than its factorization.
13301021300020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1936179 (or 1936177 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 13301021300020 its reverse (2000312010331), we get a palindrome (15301333310351).
The spelling of 13301021300020 in words is "thirteen trillion, three hundred one billion, twenty-one million, three hundred thousand, twenty".
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