Base | Representation |
---|---|
bin | 1100000110001110001101… |
… | …1110000000010100101011 |
3 | 1202002120022000001010211212 |
4 | 3001203203132000110223 |
5 | 3220411004432321331 |
6 | 44142224450143335 |
7 | 2541653022263336 |
oct | 301434336002453 |
9 | 52076260033755 |
10 | 13301035042091 |
11 | 4268a34584485 |
12 | 15a99b5881b4b |
13 | 756389073164 |
14 | 33dab87d761d |
15 | 180eccb49d2b |
hex | c18e378052b |
13301035042091 has 2 divisors, whose sum is σ = 13301035042092. Its totient is φ = 13301035042090.
The previous prime is 13301035042073. The next prime is 13301035042093. The reversal of 13301035042091 is 19024053010331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13301035042091 - 210 = 13301035041067 is a prime.
Together with 13301035042093, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13301035042093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650517521045 + 6650517521046.
It is an arithmetic number, because the mean of its divisors is an integer number (6650517521046).
Almost surely, 213301035042091 is an apocalyptic number.
13301035042091 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301035042091 is an equidigital number, since it uses as much as digits as its factorization.
13301035042091 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 32.
The spelling of 13301035042091 in words is "thirteen trillion, three hundred one billion, thirty-five million, forty-two thousand, ninety-one".
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