Base | Representation |
---|---|
bin | 1100000110001110011110… |
… | …0010100010101001010000 |
3 | 1202002120110202120001010012 |
4 | 3001203213202202221100 |
5 | 3220411124423340422 |
6 | 44142235330054052 |
7 | 2541654511641050 |
oct | 301434742425120 |
9 | 52076422501105 |
10 | 13301103340112 |
11 | 4268a6a092825 |
12 | 15a9a1471a328 |
13 | 75639a2670a3 |
14 | 33dac38d5560 |
15 | 180ed3b3b4e2 |
hex | c18e78a2a50 |
13301103340112 has 80 divisors (see below), whose sum is σ = 31189446961920. Its totient is φ = 5364375496704.
The previous prime is 13301103340099. The next prime is 13301103340121. The reversal of 13301103340112 is 21104330110331.
It is a super-3 number, since 3×133011033401123 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12763814 + ... + 13766522.
It is an arithmetic number, because the mean of its divisors is an integer number (389868087024).
Almost surely, 213301103340112 is an apocalyptic number.
It is an amenable number.
13301103340112 is an abundant number, since it is smaller than the sum of its proper divisors (17888343621808).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13301103340112 is a wasteful number, since it uses less digits than its factorization.
13301103340112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1009708 (or 1009702 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13301103340112 its reverse (21104330110331), we get a palindrome (34405433450443).
The spelling of 13301103340112 in words is "thirteen trillion, three hundred one billion, one hundred three million, three hundred forty thousand, one hundred twelve".
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