Base | Representation |
---|---|
bin | 1100000110001110011110… |
… | …0110110000010000000101 |
3 | 1202002120110211122010221112 |
4 | 3001203213212300100011 |
5 | 3220411130214210141 |
6 | 44142235405454405 |
7 | 2541654524220443 |
oct | 301434746602005 |
9 | 52076424563845 |
10 | 13301104444421 |
11 | 4268a6a777482 |
12 | 15a9a14b71405 |
13 | 75639a562921 |
14 | 33dac3b01b93 |
15 | 180ed3ca87eb |
hex | c18e79b0405 |
13301104444421 has 2 divisors, whose sum is σ = 13301104444422. Its totient is φ = 13301104444420.
The previous prime is 13301104444409. The next prime is 13301104444451. The reversal of 13301104444421 is 12444440110331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12776950164196 + 524154280225 = 3574486^2 + 723985^2 .
It is a cyclic number.
It is not a de Polignac number, because 13301104444421 - 26 = 13301104444357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301104444451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650552222210 + 6650552222211.
It is an arithmetic number, because the mean of its divisors is an integer number (6650552222211).
Almost surely, 213301104444421 is an apocalyptic number.
It is an amenable number.
13301104444421 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301104444421 is an equidigital number, since it uses as much as digits as its factorization.
13301104444421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 13301104444421 its reverse (12444440110331), we get a palindrome (25745544554752).
The spelling of 13301104444421 in words is "thirteen trillion, three hundred one billion, one hundred four million, four hundred forty-four thousand, four hundred twenty-one".
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