Base | Representation |
---|---|
bin | 10011010110110000111… |
… | …110100111110011001111 |
3 | 11201011020221100020222011 |
4 | 103112300332213303033 |
5 | 133243033202203211 |
6 | 2455013533202051 |
7 | 165045316210504 |
oct | 23266076476317 |
9 | 4634227306864 |
10 | 1330114100431 |
11 | 4731098085a6 |
12 | 195950630327 |
13 | 98576ccc08c |
14 | 48540c154ab |
15 | 248eca8b921 |
hex | 135b0fa7ccf |
1330114100431 has 2 divisors, whose sum is σ = 1330114100432. Its totient is φ = 1330114100430.
The previous prime is 1330114100429. The next prime is 1330114100443. The reversal of 1330114100431 is 1340014110331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330114100431 - 21 = 1330114100429 is a prime.
It is a super-2 number, since 2×13301141004312 (a number of 25 digits) contains 22 as substring.
Together with 1330114100429, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330114100401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665057050215 + 665057050216.
It is an arithmetic number, because the mean of its divisors is an integer number (665057050216).
Almost surely, 21330114100431 is an apocalyptic number.
1330114100431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330114100431 is an equidigital number, since it uses as much as digits as its factorization.
1330114100431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1330114100431 its reverse (1340014110331), we get a palindrome (2670128210762).
The spelling of 1330114100431 in words is "one trillion, three hundred thirty billion, one hundred fourteen million, one hundred thousand, four hundred thirty-one".
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