Base | Representation |
---|---|
bin | 1100000110001110110110… |
… | …0100001011100010010100 |
3 | 1202002120201210210002112212 |
4 | 3001203231210023202110 |
5 | 3220411331313324134 |
6 | 44142253340532552 |
7 | 2541660150134453 |
oct | 301435544134224 |
9 | 52076653702485 |
10 | 13301204433044 |
11 | 4269011160400 |
12 | 15a9a42551158 |
13 | 7563b51a11a8 |
14 | 33dad30ccb9a |
15 | 180edc959bce |
hex | c18ed90b894 |
13301204433044 has 36 divisors (see below), whose sum is σ = 25586065924692. Its totient is φ = 6045887485440.
The previous prime is 13301204433019. The next prime is 13301204433053. The reversal of 13301204433044 is 44033440210331.
It can be written as a sum of positive squares in 2 ways, for example, as 11617599571600 + 1683604861444 = 3408460^2 + 1297538^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 13301204433044.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 28624142 + ... + 29085114.
Almost surely, 213301204433044 is an apocalyptic number.
It is an amenable number.
13301204433044 is a deficient number, since it is larger than the sum of its proper divisors (12284861491648).
13301204433044 is a wasteful number, since it uses less digits than its factorization.
13301204433044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 520616 (or 520603 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 13301204433044 its reverse (44033440210331), we get a palindrome (57334644643375).
The spelling of 13301204433044 in words is "thirteen trillion, three hundred one billion, two hundred four million, four hundred thirty-three thousand, forty-four".
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