Base | Representation |
---|---|
bin | 10011010110110001011… |
… | …010001100111010100101 |
3 | 11201011021102221120112121 |
4 | 103112301122030322211 |
5 | 133243042030032331 |
6 | 2455014352145541 |
7 | 165045434522116 |
oct | 23266132147245 |
9 | 4634242846477 |
10 | 1330121330341 |
11 | 4731128a6531 |
12 | 195952b382b1 |
13 | 98578660b2b |
14 | 48541b7820d |
15 | 248ed518c11 |
hex | 135b168cea5 |
1330121330341 has 2 divisors, whose sum is σ = 1330121330342. Its totient is φ = 1330121330340.
The previous prime is 1330121330311. The next prime is 1330121330357. The reversal of 1330121330341 is 1430331210331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 789130188900 + 540991141441 = 888330^2 + 735521^2 .
It is a cyclic number.
It is not a de Polignac number, because 1330121330341 - 25 = 1330121330309 is a prime.
It is a super-2 number, since 2×13301213303412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330121330311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665060665170 + 665060665171.
It is an arithmetic number, because the mean of its divisors is an integer number (665060665171).
Almost surely, 21330121330341 is an apocalyptic number.
It is an amenable number.
1330121330341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330121330341 is an equidigital number, since it uses as much as digits as its factorization.
1330121330341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1330121330341 its reverse (1430331210331), we get a palindrome (2760452540672).
The spelling of 1330121330341 in words is "one trillion, three hundred thirty billion, one hundred twenty-one million, three hundred thirty thousand, three hundred forty-one".
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