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1330121330341 is a prime number
BaseRepresentation
bin10011010110110001011…
…010001100111010100101
311201011021102221120112121
4103112301122030322211
5133243042030032331
62455014352145541
7165045434522116
oct23266132147245
94634242846477
101330121330341
114731128a6531
12195952b382b1
1398578660b2b
1448541b7820d
15248ed518c11
hex135b168cea5

1330121330341 has 2 divisors, whose sum is σ = 1330121330342. Its totient is φ = 1330121330340.

The previous prime is 1330121330311. The next prime is 1330121330357. The reversal of 1330121330341 is 1430331210331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 789130188900 + 540991141441 = 888330^2 + 735521^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330121330341 - 25 = 1330121330309 is a prime.

It is a super-2 number, since 2×13301213303412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330121330311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665060665170 + 665060665171.

It is an arithmetic number, because the mean of its divisors is an integer number (665060665171).

Almost surely, 21330121330341 is an apocalyptic number.

It is an amenable number.

1330121330341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330121330341 is an equidigital number, since it uses as much as digits as its factorization.

1330121330341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1330121330341 its reverse (1430331210331), we get a palindrome (2760452540672).

The spelling of 1330121330341 in words is "one trillion, three hundred thirty billion, one hundred twenty-one million, three hundred thirty thousand, three hundred forty-one".