Base | Representation |
---|---|
bin | 10011010110110010000… |
… | …111001011100001110001 |
3 | 11201011022021010121110202 |
4 | 103112302013023201301 |
5 | 133243103034334022 |
6 | 2455015453004545 |
7 | 165045636660452 |
oct | 23266207134161 |
9 | 4634267117422 |
10 | 1330133121137 |
11 | 47311951a097 |
12 | 195956a83755 |
13 | 9857ac2b832 |
14 | 48543567129 |
15 | 248ee597592 |
hex | 135b21cb871 |
1330133121137 has 2 divisors, whose sum is σ = 1330133121138. Its totient is φ = 1330133121136.
The previous prime is 1330133121101. The next prime is 1330133121139. The reversal of 1330133121137 is 7311213310331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1229206820416 + 100926300721 = 1108696^2 + 317689^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330133121137 is a prime.
Together with 1330133121139, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1330133121139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665066560568 + 665066560569.
It is an arithmetic number, because the mean of its divisors is an integer number (665066560569).
Almost surely, 21330133121137 is an apocalyptic number.
It is an amenable number.
1330133121137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330133121137 is an equidigital number, since it uses as much as digits as its factorization.
1330133121137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 29.
Adding to 1330133121137 its reverse (7311213310331), we get a palindrome (8641346431468).
The spelling of 1330133121137 in words is "one trillion, three hundred thirty billion, one hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-seven".
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