13301422011043 has 2 divisors, whose sum is σ = 13301422011044. Its totient is φ = 13301422011042.

The previous prime is 13301422011041. The next prime is 13301422011049. The reversal of 13301422011043 is 34011022410331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13301422011043 - 2¹ = 13301422011041 is a prime.

Together with 13301422011041, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13301422010999 and 13301422011017.

It is not a weakly prime, because it can be changed into another prime (13301422011041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650711005521 + 6650711005522.

It is an arithmetic number, because the mean of its divisors is an integer number (6650711005522).

Almost surely, 2^{13301422011043} is an apocalyptic number.

13301422011043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301422011043 is an equidigital number, since it uses as much as digits as its factorization.

13301422011043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13301422011043 its reverse (34011022410331), we get a palindrome (47312444421374).

The spelling of 13301422011043 in words is "thirteen trillion, three hundred one billion, four hundred twenty-two million, eleven thousand, forty-three".