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1330211100157 is a prime number
BaseRepresentation
bin10011010110110110110…
…000101001010111111101
311201011111200212100120121
4103112312300221113331
5133243233020201112
62455031320214541
7165050604535522
oct23266660512775
94634450770517
101330211100157
1147315953a965
1219597900a451
1398591132074
144854da65149
152490634c407
hex135b6c295fd

1330211100157 has 2 divisors, whose sum is σ = 1330211100158. Its totient is φ = 1330211100156.

The previous prime is 1330211100137. The next prime is 1330211100181. The reversal of 1330211100157 is 7510011120331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1063990187001 + 266220913156 = 1031499^2 + 515966^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330211100157 - 215 = 1330211067389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330211100137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665105550078 + 665105550079.

It is an arithmetic number, because the mean of its divisors is an integer number (665105550079).

Almost surely, 21330211100157 is an apocalyptic number.

It is an amenable number.

1330211100157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330211100157 is an equidigital number, since it uses as much as digits as its factorization.

1330211100157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630, while the sum is 25.

Adding to 1330211100157 its reverse (7510011120331), we get a palindrome (8840222220488).

The spelling of 1330211100157 in words is "one trillion, three hundred thirty billion, two hundred eleven million, one hundred thousand, one hundred fifty-seven".