Base | Representation |
---|---|
bin | 10011010110110110110… |
… | …000101001011110001101 |
3 | 11201011111200212101010102 |
4 | 103112312300221132031 |
5 | 133243233020204212 |
6 | 2455031320220445 |
7 | 165050604536633 |
oct | 23266660513615 |
9 | 4634450771112 |
10 | 1330211100557 |
11 | 473159540199 |
12 | 19597900a725 |
13 | 985911322c1 |
14 | 4854da65353 |
15 | 2490634c5c2 |
hex | 135b6c2978d |
1330211100557 has 2 divisors, whose sum is σ = 1330211100558. Its totient is φ = 1330211100556.
The previous prime is 1330211100499. The next prime is 1330211100599. The reversal of 1330211100557 is 7550011120331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1001172343396 + 329038757161 = 1000586^2 + 573619^2 .
It is a cyclic number.
It is not a de Polignac number, because 1330211100557 - 28 = 1330211100301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330211100157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665105550278 + 665105550279.
It is an arithmetic number, because the mean of its divisors is an integer number (665105550279).
Almost surely, 21330211100557 is an apocalyptic number.
It is an amenable number.
1330211100557 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330211100557 is an equidigital number, since it uses as much as digits as its factorization.
1330211100557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3150, while the sum is 29.
Adding to 1330211100557 its reverse (7550011120331), we get a palindrome (8880222220888).
The spelling of 1330211100557 in words is "one trillion, three hundred thirty billion, two hundred eleven million, one hundred thousand, five hundred fifty-seven".
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