Base | Representation |
---|---|
bin | 11000110001101111… |
… | …00100101000100000 |
3 | 1021100001021212100201 |
4 | 30120313210220200 |
5 | 204220320414130 |
6 | 10035542354544 |
7 | 650432115553 |
oct | 143067445040 |
9 | 37301255321 |
10 | 13302123040 |
11 | 5706779a18 |
12 | 26b2a2ba54 |
13 | 133cb63c2b |
14 | 90293269a |
15 | 52cc2ebca |
hex | 318de4a20 |
13302123040 has 24 divisors (see below), whose sum is σ = 31426266060. Its totient is φ = 5320849152.
The previous prime is 13302123019. The next prime is 13302123061. The reversal of 13302123040 is 4032120331.
It is an interprime number because it is at equal distance from previous prime (13302123019) and next prime (13302123061).
It can be written as a sum of positive squares in 2 ways, for example, as 10818496144 + 2483626896 = 104012^2 + 49836^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13302122999 and 13302123017.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41568975 + ... + 41569294.
Almost surely, 213302123040 is an apocalyptic number.
13302123040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13302123040 is an abundant number, since it is smaller than the sum of its proper divisors (18124143020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13302123040 is an equidigital number, since it uses as much as digits as its factorization.
13302123040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83138284 (or 83138276 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13302123040 its reverse (4032120331), we get a palindrome (17334243371).
The spelling of 13302123040 in words is "thirteen billion, three hundred two million, one hundred twenty-three thousand, forty".
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