13302131111 has 2 divisors, whose sum is σ = 13302131112. Its totient is φ = 13302131110.

The previous prime is 13302131071. The next prime is 13302131113. The reversal of 13302131111 is 11113120331.

It is a strong prime.

It is an emirp because it is prime and its reverse (11113120331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13302131111 - 2⁶ = 13302131047 is a prime.

Together with 13302131113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13302131111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13302131113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651065555 + 6651065556.

It is an arithmetic number, because the mean of its divisors is an integer number (6651065556).

Almost surely, 2^13302131111 is an apocalyptic number.

13302131111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13302131111 is an equidigital number, since it uses as much as digits as its factorization.

13302131111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13302131111 its reverse (11113120331), we get a palindrome (24415251442).

The spelling of 13302131111 in words is "thirteen billion, three hundred two million, one hundred thirty-one thousand, one hundred eleven".