Base | Representation |
---|---|
bin | 1100000110010010010101… |
… | …1101011110110011100111 |
3 | 1202002200011011100122102201 |
4 | 3001210211131132303213 |
5 | 3220420241400413223 |
6 | 44142530400315331 |
7 | 2542022325054142 |
oct | 301444535366347 |
9 | 52080134318381 |
10 | 13302142201063 |
11 | 42694525393a1 |
12 | 15aa064612b47 |
13 | 75650455c501 |
14 | 33db8187b059 |
15 | 181044e46ead |
hex | c192575ece7 |
13302142201063 has 2 divisors, whose sum is σ = 13302142201064. Its totient is φ = 13302142201062.
The previous prime is 13302142201039. The next prime is 13302142201133. The reversal of 13302142201063 is 36010224120331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13302142201063 - 25 = 13302142201031 is a prime.
It is a super-4 number, since 4×133021422010634 (a number of 54 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13302142201363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651071100531 + 6651071100532.
It is an arithmetic number, because the mean of its divisors is an integer number (6651071100532).
Almost surely, 213302142201063 is an apocalyptic number.
13302142201063 is a deficient number, since it is larger than the sum of its proper divisors (1).
13302142201063 is an equidigital number, since it uses as much as digits as its factorization.
13302142201063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13302142201063 its reverse (36010224120331), we get a palindrome (49312366321394).
The spelling of 13302142201063 in words is "thirteen trillion, three hundred two billion, one hundred forty-two million, two hundred one thousand, sixty-three".
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