Base | Representation |
---|---|
bin | 11110001111110001110010… |
… | …111011000000011010000111 |
3 | 122110000010110121222212000202 |
4 | 132033301302323000122013 |
5 | 114413443020210200003 |
6 | 1150531050424401115 |
7 | 40006533513224645 |
oct | 3617616273003207 |
9 | 573003417885022 |
10 | 133025655162503 |
11 | 39427955405244 |
12 | 12b0531a91619b |
13 | 592c35b28c2cc |
14 | 24bc694464195 |
15 | 105a481277088 |
hex | 78fc72ec0687 |
133025655162503 has 2 divisors, whose sum is σ = 133025655162504. Its totient is φ = 133025655162502.
The previous prime is 133025655162373. The next prime is 133025655162563. The reversal of 133025655162503 is 305261556520331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133025655162503 is a prime.
It is a super-2 number, since 2×1330256551625032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133025655162563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66512827581251 + 66512827581252.
It is an arithmetic number, because the mean of its divisors is an integer number (66512827581252).
Almost surely, 2133025655162503 is an apocalyptic number.
133025655162503 is a deficient number, since it is larger than the sum of its proper divisors (1).
133025655162503 is an equidigital number, since it uses as much as digits as its factorization.
133025655162503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2430000, while the sum is 47.
The spelling of 133025655162503 in words is "one hundred thirty-three trillion, twenty-five billion, six hundred fifty-five million, one hundred sixty-two thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •