Base | Representation |
---|---|
bin | 11110001111110110111000… |
… | …110001011010011111001100 |
3 | 122110000122120121212000002110 |
4 | 132033312320301122133030 |
5 | 114414040214214122200 |
6 | 1150533353114224020 |
7 | 40010116134602610 |
oct | 3617667061323714 |
9 | 573018517760073 |
10 | 133031122020300 |
11 | 3942a2002a2439 |
12 | 12b063a5725010 |
13 | 592ca1ca6a9ca |
14 | 24bca52531340 |
15 | 105a6a119bb50 |
hex | 78fdb8c5a7cc |
133031122020300 has 72 divisors (see below), whose sum is σ = 439889576820736. Its totient is φ = 30407113604160.
The previous prime is 133031122020217. The next prime is 133031122020317. The reversal of 133031122020300 is 3020221130331.
It is a super-2 number, since 2×1330311220203002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31674074572 + ... + 31674078771.
Almost surely, 2133031122020300 is an apocalyptic number.
133031122020300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133031122020300 is an abundant number, since it is smaller than the sum of its proper divisors (306858454800436).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133031122020300 is a wasteful number, since it uses less digits than its factorization.
133031122020300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63348153367 (or 63348153360 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 133031122020300 its reverse (3020221130331), we get a palindrome (136051343150631).
The spelling of 133031122020300 in words is "one hundred thirty-three trillion, thirty-one billion, one hundred twenty-two million, twenty thousand, three hundred".
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