Base | Representation |
---|---|
bin | 11110001111110110111111… |
… | …010101101101111010011111 |
3 | 122110000122212022011201201002 |
4 | 132033312333111231322133 |
5 | 114414040430420402401 |
6 | 1150533412051540515 |
7 | 40010121643244342 |
oct | 3617667725557237 |
9 | 573018768151632 |
10 | 133031232200351 |
11 | 3942a257507331 |
12 | 12b064165ba73b |
13 | 592ca39836cc4 |
14 | 24bca63012459 |
15 | 105a6aabb2a6b |
hex | 78fdbf56de9f |
133031232200351 has 2 divisors, whose sum is σ = 133031232200352. Its totient is φ = 133031232200350.
The previous prime is 133031232200311. The next prime is 133031232200353. The reversal of 133031232200351 is 153002232130331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133031232200351 - 242 = 128633185689247 is a prime.
Together with 133031232200353, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133031232200353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515616100175 + 66515616100176.
It is an arithmetic number, because the mean of its divisors is an integer number (66515616100176).
Almost surely, 2133031232200351 is an apocalyptic number.
133031232200351 is a deficient number, since it is larger than the sum of its proper divisors (1).
133031232200351 is an equidigital number, since it uses as much as digits as its factorization.
133031232200351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 133031232200351 its reverse (153002232130331), we get a palindrome (286033464330682).
The spelling of 133031232200351 in words is "one hundred thirty-three trillion, thirty-one billion, two hundred thirty-two million, two hundred thousand, three hundred fifty-one".
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